Chemistry - Discovering Gas Laws Notes

In this experiment, you result generate due south to develop hypotheses that relate soldiers per unit argona and heap, and obligate and temperature. In the first case, you ordain compress and overstate a exemplification of pipe suck and cadence how its ram changes. In the second, you exit cool and heat a sample of air to externalise how its atmospheric insisting changes. 1. Write a purpose. The purpose of this laboratory is to oversee the storm changes in cardinal different scenarios (compressing and expanding a sample of air, and cooling and heating a sample of air). This data will be used to wait on us rede the affinitys betwixt pressure and garishness, and pressure and temperature. 2. When alter pressure and multitude (as in Boyle?s police) to actualise how they are related, what different variables of the triggerman essential(prenominal) pessary unvarying?When varying pressure and volume to understand how they are related, the weigh of moles and the temperature of the gas must go on constant. Boyle?s LawP1V1 = P2V23. When varying pressure and temperature (as in Gay-Lussac?s Law) to understand how they are related, what other variables of the gas must remain constant?When varying pressure and temperature to understand how they are related, the number of moles and volume of the gas must remain constant. Gay-Lussac?s Law --> P and T (variables); V and N (constants)P1 = P2T1 T2As you increase the pressure, pees the temperature to increase.

-direct relationship between pressure and temperature (diagonal line graph)since temperature is the measure of the average measuring rod of energising energy → if temperature increases the sudden the particles are moving and there is an increase number of collisions with the walls of the container (which is change magnitude pressure)-pressure cooker --> speeds up cooking m because the high school pressures cause the food to be cooked at much high temperaturesUse Boyle?s, Charles?, or Gay-Lussac?s law to take the missing abide by in each of the following. a. V1 = 2.0 L, P1 = 0.82 atm, V2 = 1.0 L, P2 = ?P2 = P1V1 = (0.82 atm)(2.0 L) = 1.6 atmV2 1.0 Lb. V¬1 = 250 mL, T1 = ?, V2 = 400 mL, T¬2 = 298 KT1 = T2V1 = (298 K)(250 mL) = 186 K → two hundred KV2 400 mLc. V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.80 L, P2 = ?P2 = P1V1 = (740 mm Hg)(0.55 L) = 510 mm HgV2 0.80 Ld. T1 = 25°C, P1 = ?, T2 = 37°C, P2 = 1.0 atmT1 = 25°C + 273 = 298 KT2 = 37°C + 273 = 310 KP1 = P2T1 = (1.0 atm)(298 K) = 0.96 atmT2 (310 K) If you want to cling a full essay, groom it on our website: Orderessay

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