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None Provided5 Hess? Law:Work to be done: suffer enthalpy change by measuring temperature change of a reaction. Chemicals and apparatus: Thermometer Scale Isolator NaOH, solid NaOH, 0.50M solution Acetic acid, 0.50M and 0.25M science lab: reply 1) The temperature of 200ml water that I poured into the isolator was 23.0?C. To that I added 1.97g solid NaOH and tolerate the reaction take place. After a while I measured the temperature to 24.9?C ? rT = 1.9?C. The calculate of mole NaOH is 1.97 / 40 = 0.049 mol. answer 2) In this experiment I used 100ml 0.50M acetic acid, and to that I added 100ml 0.50M liquid NaOH.

The temperature of the acetic acid was 23?C and the temperature of the NaOH was 22?C. So the average, and the upshot I use will be 22.5?C. After the reaction the temperature of the solution was 25?C, so rT = 2.5?C. The number of mole NaOH is 0.50 * .100 = 0.050 mol. Reaction 3) In the third reaction I used 200ml 0.25M acetic acid with a temperature of 22.5?C, t...If you want to set a full essay, order it on our website: OrderEssay.net

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